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1.6x^2+6.9x-176=0
a = 1.6; b = 6.9; c = -176;
Δ = b2-4ac
Δ = 6.92-4·1.6·(-176)
Δ = 1174.01
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6.9)-\sqrt{1174.01}}{2*1.6}=\frac{-6.9-\sqrt{1174.01}}{3.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6.9)+\sqrt{1174.01}}{2*1.6}=\frac{-6.9+\sqrt{1174.01}}{3.2} $
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